Q. [+15]
( 26x - 4y + 3 ) + ( 5x + 3y - 1 )
BeA thn depan sj?._.![]()
( 26x - 4y + 3 ) + ( 5x + 3y - 1 )
BeA thn depan sj?._.
Penjelasan dengan langkah-langkah:
( 26x - 4y + 3 ) + ( 5x + 3y - 1 )
= ( 26x + 5x ) + ( - 4y + 3y ) + ( 3 + ( - 1 ))
= 31x + ( - 4y + 3y ) + ( 3 + ( - 1 ))
= 31x - y + ( 3 + ( - 1 ))
= 31x - y + 2
→ (26x - 4y + 3) + (5x + 3y - 1)
→ 26x - 4y + 3 + 5x + 3y - 1
→ 26x + 5x - 4y + 3y + 3 - 1
→ 31x - y + 2
[tex]\purple{\boxed{\blue{\boxed{\green{\star{\orange{\ \: \: \mathcal{JK} \: \: \: {\green{\star}}}}}}}}} [/tex]
